w w w . Quantitative Aptitude Tricks B Quantitative Aptitude Tricks - PDF a Download n k Topics : www.BankExamsToday.com E 1. Simplification 2. Number Series x 3. Percentage a 4. Profit and Loss 5. Simple Interest and Compound Interest m 6. Ratio and Proportion s 7. Time and Work 8. Time Speed and Distance T o #1 SIMPLIFICATION d a Q1. y 812 ÷ 162 of 323 × √256 = 2? . Sol : c (23)12 ÷ (24)2 of (25)3 × 16 = 2 o 236÷ 28 of 215 × 24 = 2? m 217 = 2? ? = 17 Q2. 108 ÷ 36 of 1/ + 2/ × 31/ = ? 4 5 4 Sol : 108 ÷ 9 + 2/ × 13/ = ? 5 4 12+13/ 10 ? = 133/ 10 Q3. 331/ % of 633 + 129 = 662/ % of = ? 3 3 Sol : 1/ × 633 + 129 = 2/ ×? 3 3 ( 211+129 )×3/ = ? 2 ? = 340×3/ = 170×3 = 510 2 By Ramandeep Singh Page1 w w w . More Tricks on SimplificQautiaonn taintad tDivoew Anlpoatidt uPdDeF T: Crilcickks Here B a n #2 NUMBER SERIES k www.BankExamsToday.com E Basic Concept Starts From Here : Click Here x Q1. a m In each series only one number is wrong. Find out the Wrong number.  5531, 5506, 5425, 5304, 5135, 4910, 4621 (IBPS PO 2012) s Hint: -72, -92, -112 T o  1, 3, 10, 36, 152, 760, 4632 (IBPS PO 2012) d a Hint : ×1+2, ×2+4, ×3+6 ... y  4, 3, 9, 34, 96, 219, 435 (IBPS PO 2012) . Hint : +13 -2 , +23 -2 , +33 -2, ... c  5, 7, 16, 57, 244, 1245, 7506 (Allahabad Bank PO 2010) o Hint : ×1+12,×2+22 m  2.5,3.5,6.5,15.5,41.25,126.75 (Allahabad Bank PO 2010) Hint : ×1/2+1/2, ×1+1 , ×3/2+3/2 .... #3 PERCENTAGE Basic Concepts Starts Here : Click Here Q1. If the income of Ram is 10% more than that of Shayam's income. How much % Shyam's income is less than that of Ram's income ? Method I. By using formula less% = r/100+r ×100 = 10/100+10 × 100 = 10/110 ×100 = 9 1/11% Method II. By Ramandeep Singh Page2 w w w . Quantitative Aptitude Tricks B a n k www.BankExamsToday.com E x a m s Q2. T A man spends 40% on food, 20% on house rent, 12% on travel and 10% on education. After all these expenditure he saved Rs. 7200. Find the amount spent o on travel ? d Method I. a Let total income x total expenditure y = x × (40%+20%+12%+10%) . = x × 82% Total saving = x - x × 82% c = x × 18% o Then x × 18% = 7200 m x = 7200/18×100 = 40,000 Expenditure on travel = 12% x × 12% = 40,000×12/100 = Rs. 4800 Method II. Total income = 100% - represent total 100% -82% = 18% (saving) Expenditure on Travel = 7200/18×12 = 4800 Q3. By Ramandeep Singh Page3 w w w . When numerator of a fraQcutiaonn tisit iantcirveea sAedp tbiyt u10d%e Tanrdic dkesnominator decreased by B 20% the resultant fraction becomes 5/8. Find the original fraction ? a Method I. Let the original fraction be x/y then - n k www.BankExamsToday.com E x a m s T o d a y . Method II. Given Fraction = 5/8 c Original fraction = 5/8×80/110 o = 5/11 Ans. m Q4. If the length of a rectangle is increased by 20% and breath is decreased by 10%. Find the net% change in the area of that rectangle. Sol: net% change = x+y+ x×y/100 (+20)×(-10)/100 = +10-2 =8 Increase % = 8% Ans. Q5. A reduction of 10% in the price of tea would enable and purchase to obtain 3 Kg. more for 2700 Rs. Find the reduced rate (new rate ) of tea ? Sol : 10% 2700 = Rs. 270 Rs. 270 is the rate of 3 kg. of tea By Ramandeep Singh Page4 w w w . 1 kg of tea = Rs. 90/- kg,Quantitative Aptitude Tricks B a #4 PROFIT AND LOSS n Basic Concept Starts Here : Click Here k www.BankExamsToday.com Statement E A purchase an article at Rs 40 Rs. and sells it to B at rs. 50 and B sells its to C at x Rs. 30 a m s T o d a y . For A, Profit = 50-40 = 10 For B, Loss = 50 -30 = 20 c o For A, P =SP-CP For B, L= CP-SP m For A, Percent Profit = Profit of A/CP of A×100 For B, Percent loss = Loss of B/CP of B×100 For A, 10/40×100 = 25% For B, 20/50×100 = 40% P% = P/CP×100 L% = L/CP×100 Q1. A person purchased an article for Rs. 80 and sold it for Rs. 100.Find his % profit. Sol: CP of the article = Rs. 80 SP of the article = Rs. 100 Profit of the person = 100-80 = Rs. 20 % Profit of the person = Profit /CP×100 %P = 20/80×100 %P = 25% By Ramandeep Singh Page5 w w w . Trick: Quantitative Aptitude Tricks B %P = 20/80×100 = 25% a Q2. n k A dishonest swhopwkeewper .seBllsagoondsk atE hisx coast pmrices buTt uosesd a aweiygh.t cof o900m gm for a kg. weight. Find his gain percent. E Sol: x The Cp of Shopkeeper = 900 gm The Sp of Shopkeeper a = 1000 gm ( 1kg = 1000 gm ) m The profit of shopkeeper s = 1000 -900 = 100 gm % profit shopkeeper T = Profit ofshopkeeper/ ×100 CP of shopkeeper o %P = 100/ ×100 = 111/ % 900 9 d Q3. a A person got 5% loss by selling an article for Rs. 1045. At what price should the y article be sold to earn 5% profit ? . Sol: Trick : c New SP = 1045/95×105 = 1155 o m Q4. A person sold an article at profit of 12%. If he had sold it Rs. 3.60 more, he would have gain 18%. What is the cost price ? Sol: Trick : CP = 3.60/6×100 = Rs. 60 Q5. If the CP of 12 articles is equal to the SP of 9 articles. Find the gain or loss. Sol : Let the CP of each article be Rs. 1 Then CP of 9 articles = Rs. 9 SP of 9 articles = Rs. 12 Gain % = 3/9×100 = 331/ % 3 # 5 SIMPLE AND COMPOUND INTEREST Basic Concept Starts From Here : Click Here By Ramandeep Singh Page6 w w w . Quantitative Aptitude Tricks Q1. B a At what rate of interest per annum will a sum double itself in 8 years ? Sol: n Trick : k www.BankExamsToday.com E x a m s T o d a Q2. y A sum of money double itself at compound interest in 15 years. In how many . years will it become eight times. c Trick : o m By Ramandeep Singh Page7 w w w . t = 45 years Quantitative Aptitude Tricks 2 B a n #6 RATIO AND PROPORTION k www.BankExamsToday.com Q1. E The ratio between the length and the breadth of a rectabgular field is 5:4 x respectively. If the perimeter of that field is 360 meters. what is the breadth of a that field in meters ? m Sol : Perimeter = 2(5+4) = 18 s Mean value of 18 = 360 T Breadth = 360/ × 4 = 80 meters 18 o Q2. d A bag contains 50 P, 25 P and 10 P coins in the ratio 5:9:4 amounting to Rs. 206. a Find the number of coins of each type. y Sol: Let the number of 50P,25P and 10P coins be 5x,9x and 4x respectively . 5x/2+9x/4+4x/10 = 206 c 50x + 45x + 8x = 4120 o 103x = 4120 x = 40 m No. of 50 P coins = 5×40 = 200 No. of 25 P coins = 4×40 = 160 No. of 10 P coins = 9×40 = 360 Q3. A mixture contains alcohol and water in the ratio of 4:3. If 5 liters of water is added to the mixture the ratio becomes 4:5. Find the quantities of alcohol in the given mixture. Sol: Let the quantity of alcohal and water be 4x liters and 3x liters respectively. 4x/ = 4/5 3x+5 8x =20 x = 2.5 Q4. A:B = 5:9 and B:C = 4:7 Find A:B:C. Sol: By Ramandeep Singh Page8 w w w . Quantitative Aptitude Tricks B a n k www.BankExamsToday.com E x #7 TIME AND WORK a m Q1. s A and B together can complete a piece of work in 4 days. If A alone can complete T the same work in 12 days, in how many days can B alone complete that work ?(S.S.C.2003) o Sol: d a y . c o m Q2. X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last ? (Bank PO,2004) Sol: By Ramandeep Singh Page9 w w w . Quantitative Aptitude Tricks B a n k www.BankExamsToday.com E x a m s T o d a Q3. y A is thrice as good a workman as B and together is able to finish a job in 60 days less than B. Working together, they can do it in ? . Sol : c o m #8 TIME, SPEED AND DISTANCE By Ramandeep Singh Page10